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Git4.py
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Git4.py
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#!/usr/bin/env python3
# -*- coding: utf-8 -*-
"""
Created on Thu Nov 11 13:14:15 2021
@author: magelineduquesne
"""
#%% IMPORT MODULES
import os
import pandas as pd
import numpy as np
import matplotlib.pyplot as plt
import warnings
import random as rd
import scipy.stats
warnings.filterwarnings("error")
warnings.filterwarnings("ignore", category=DeprecationWarning)
# import scipy as scipy
# from scipy import optimize
# import scipy.misc
# from scipy.misc import derivative
# import scipy.stats as stats
#%% Get files from directory
dirname = os.path.dirname(__file__)
# meanget monthly temperature [C]
temperature= pd.read_csv(dirname+"/temperature.txt")
T_m=temperature.T.to_numpy()[0]
# hourly precipitation intensity [mm/h] for the period 01/01/2000 to 31/12/2005
precipitation=pd.read_csv(dirname+"/P.txt").T.to_numpy()[0]
# Changes in monthly temperature [degrees C]
temperature_change= pd.read_csv(dirname+"/temperature_change.txt")
T_c=temperature_change.T.to_numpy()[0]
# monthly mean crop coefficient [-] (average among all the crops and soil uses of the basin
cropcoeff=pd.read_csv(dirname+"/kc.txt")
K_c=cropcoeff.T.to_numpy()[0]
# instantaneous discharge at hourly time step [m3/s] for the period 01/01/2000 to 31/12/2004
Q_obs=pd.read_csv(dirname+"/Q_obs.txt").T.to_numpy()[0]
# Area rating curve
# A_rating[0] = area [m2] at lake level 0m
extract=pd.read_csv(dirname+"/area_rating_curve.txt").T.to_numpy()[0]
A_rating = [int(ele[13:]) for ele in extract[1:]]
# changes in monthly mean rainfall intensity of rainy days [%]
alpha_c=pd.read_csv(dirname+"/alpha_change.txt").T.to_numpy()[0]
#temperature in a climate change scenario [degrees C]
T_future=T_m+T_c
# change in monthly occurence of rainy days [%]
lambda_c=pd.read_csv(dirname+"/lambda_change.txt").T.to_numpy()[0]
#%% set up gobal PARAMETERS
s_w = 0.25 # [-] Wilting point
s_1 = 0.4 # [-] soil moisture above which plants transpire at kc*ET0
n = 0.3 # [-] Porosity
Q_b = 7 # [m3/s] Base flow
t_sup = 22 # [h] superficial residence time
A = 4000*1e6 # [m²] area of the basin
phi = 38 # [degrees] latitude of the basin
# these are the 'free parameters' : they will be determined during next week (session 2 of the project)
# here is a proposed average value that is the right order of magnitude
K_sat = 1e-6 # [m/s] Saturated hydraulic conductivity
K_sat_h = K_sat*3600 # [m/h] Saturated hydraulic conductivity
c = 10 # [-] exponent of ksat for the equation k = ksat * s^c
t_sub = 200 # [h] mean sub-superficial residence time
z = 1000 # [mm] root zone thickness
Qcity = 1 # [m3/s] what does it describe ?
day_month = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31] #"day_month": number of days for each month
month_end = np.cumsum(day_month)-1 #"month_end": last day of each month
month_start = month_end-day_month+1
#Thornthwaite equation
lat = phi #latitude of the site (degrees)
D = [k for k in range(365)] #day of the year
delta = [0.409*np.sin(2*np.pi*d/365-1.39) for d in D] # [-]
omega_s = [np.arccos(-np.tan(lat*np.pi/180)*np.tan(i)) for i in delta] # [rad]
N_D = [24*o/np.pi for o in omega_s] # [h] number of daylight hours of day d
N_m = [np.mean(N_D[month_start[m]:month_end[m]]) for m in range(12)] # [h] mean daylight hours of month m
Ii = np.sum([np.power(T_m[i]/5, 1.514) for i in range(12)]) # heat index [-]
a = 6.75e-7 * Ii**3 - 7.71e-5 * Ii**2 + 1.79e-2 * Ii + 0.49 # experimental exponent [-]
# monthly average potential evapotranspiration :
ET_0 = [16*N_m[i] / 12 * (10*T_m[i]/Ii)**a / (24*day_month[i]) for i in range(12)] # [mm/h]
month_name = ["January","February","March","April","May","June","July","August","September","October","November","December"]
#%% Define the auxiliairy functions
def ET_0(T):
"""
-INPUT: Monthly temperature
- OUTPUT : Monthly average potential evapotranspiration in [mm/h]
"""
evap=[16*N_m[i] / 12 * (10*T[i]/Ii)**a / (24*day_month[i]) for i in range(12)]
return evap
def month(t):
"""
Inputs :
- t a time in hours, given from January 1st as a reference
Ouptuts :
- the number of the month the given hour is in.
Month 0 corresponds to January, and month 11 is December.
month(t) calculates the month in which the given hour is in, regardless if the year.
The hour 0 must ALWAYS correspond to a January 1st in some year.
"""
j= (t//24)%365 # jour de l'année
if j >= month_start[11]:
return 11
else:
m=0
while j >= month_start[m]:
m=m+1
return m-1
########################################
def f_ET(t,s,T=T_m):
"""
Input :
- hour [h] at which the computation is done
- s [-] soil moisture at the given time
- T [degrees °C] monthly temperature
Output :
- ET [mm/h] the evapotranspiration
Works with the following model of evapotranspiration :
if s < s_w (wilting point), ET = 0
if s > s_1 (too much water), ET = ET_0 * K_c
else : linear interpolation between 0 and ET_0 * K_c
"""
Evap0=ET_0(T)
m = month(t)
if s <= s_w:
return 0
elif (s > s_w and s < s_1):
return Evap0[m] * K_c[m] / (s_1-s_w) * (s-s_w)
else:
return Evap0[m] * K_c[m]
################################
def downscaling(Pdaily):
"""
Downscale daily precipitation to hourly precipitation assuming that hourly
rainfall are exponentially distributed.
INPUT
"Pdaily": precipitation at daily timestep
OUTPUT
"Phourly": precipitation at hourly time step
if "Pdaily" is in [mm/day], "Phourly" is in [mm/h]
"""
Phourly = np.empty((len(Pdaily)*24,))
for i in range(len(Pdaily)):
#print(i)
distr = -np.log(np.random.rand(24,))
sumdistr = np.sum(distr)
Phourly[i*24:(i+1)*24] = Pdaily[i]*distr/sumdistr
return Phourly
################################
def rel_diff(a, b, ndigits=None):
"""
Input :
- a, scalar
- b, scalar
- ndigits, optional parameter, None by default. IF an integer is
entered, the result will be displayed roundedwith this number of
decimals. None outpus the result without rounding it.
Output :
(a-b)/b *100
ie the relative difference in percentage between a and b (b being the reference)
"""
return round((a-b)/b * 100, ndigits=ndigits)
#%% Hydrological model
# 1. hydr_model models the hydrological quantites according to the parameters
# 2. plot_model plots the differents curves that the model gives out
# 3. check_model checks if the model is correct using the different balance equations
def hydr_model(K_sat, c, t_sub, z, P, K_c, n_years, s_0 = 0, V_sup_0 = 0, V_sub_0 = 0,T=T_m):
"""
Inputs :
- K_sat [m/s] is the saturated hydraulic conductivity (free parameter)
- c [-] is the exponent of the hydraulic conductivity law (K = K_sat * s**c) (free parameter)
- t_sub [h] is the mean sub-superficial residence time (free parameter)
- z [mm] is the root zone thickness (free parameter)
- P [mm/h] is the hourly precipitation, is a vector !
- K_c [-] is the crop coefficient representative of the whole area
- n_years [years] is the number of years to process
Optional :
- s_0 [-] soil moisture at time t=0. Defaults to 0.
- V_sup_0 [m3] Superficial volume of water at time t=0. Defaults to 0.
- V_sub_0 [m3] Sub-superficial volume of water at time t=0. Defaults to 0.
- T [degrees °C] monthly temperature, can be changed in a climate change scenario
Output :
- Q [m3/s] the total discharge
- R [mm/h] the runoff -> possible to change unit if not convenient
- I [mm/h] the infiltration -> possible to change unit if not convenient
- s [-] the soil saturation
- L [mm/h] the leaching -> possible to change unit if not convenient
- ET [mm/h] the actual evapotranspiration
This hydrological model uses a lot of other functions to compute the associated discharges.
It works with a time step of one hour and does all the computations according to this time step.
This function also uses the following parameters (defined in the beginning of the notebook) :
- s_w [-] Wilting point
- s_1 [-] soil moisture threshold
- n [-] soil porosity
- Q_b [m3/s] base flow
- t_sup [h] the average superficial residence time
- A [m2] the area of the basin
- phi [degrees] the latitude of the basin
If you feel anything is missing in this description, please add it !
"""
# Verify that the inputs' length are correct
if len(P) != 365 * 24 * n_years:
print("Warning ! The precipitation file is too long for the number of years indicated.\
Truncating the file to the correct length")
P = P[:365*24*n_years].copy()
# count the number of errors
error_count = 0
# initalize the output vectors
n_steps = n_years * 365 * 24
Q = [0 for i in range(n_steps)]
R = Q.copy()
I = Q.copy()
s = Q.copy()
L = Q.copy()
ET = Q.copy()
# and also :
global q_sup
global q_sub
q_sup = Q.copy()
q_sub = Q.copy()
# initializing s, q_sup, q_sub & Q
s[0] = s_0
q_sup[0] = V_sup_0 / t_sup
q_sub[0] = V_sub_0 / t_sub
Q[0] = A*(q_sup[0] + q_sub[0]) + Q_b
# for each time step do
for t in range(n_steps):
# Infiltration
I[t] = min(P[t], K_sat*1000*3600) # [mm/h]
# Runoff
R[t] = P[t] - I[t] # [mm/h]
# Evapotranspiration
ET[t] = f_ET(t, s[t],T) #[mm/h]
# Leaching
# parfois le programme s'arrête, la suite est pour stopper proprement
# le programme a ce moment
try:
L[t] =1000*3600*( K_sat * s[t]**c) # [mm/h]
except:
print("program has a problem with L[t] = K_sat * s[t]**c # [mm/h]")
print("L[t] = ", L[t])
print("K_sat = ", K_sat)
print("s[t] = ", s[t])
print("c = ", c)
error_count += 1
# euler integration :
dt = 1 # [h]
# soil moisture
try :
s[t+1] = s[t] + dt * (I[t]-ET[t]-L[t])/(n*z)
if s[t+1] < 0:
# print("\nWARNING !")
# print(" Soil moisture negative (value = "+ str(s[t+1]) + ") for time t="+ str(t+1))
# ans = input("Ignore and set value to 0 ? [y] / [n] ")
# if ans == "y":
# print(" Setting value to 0\n")
# elif ans == "n":
# print("Aborting...")
# raise ValueError("The value of the soil moisture is negative !")
s[t+1] = 0
# error_count += 1
elif s[t+1] > 1:
s[t+1] = 1
# error_count += 0.0001
except IndexError:
break
# q_sub & q_sup
q_sub[t+1] = q_sub[t] + dt/t_sub * (L[t] - q_sub[t]) #[mm/h]
q_sup[t+1] = q_sup[t] + dt/t_sup * (R[t] - q_sup[t]) #[mm/h]
# Q
Q[t+1] = A * (q_sup[t+1] + q_sub[t+1])/1000/3600 + Q_b
return [Q, R, I, s, L, ET]
##################################################
def plot_model(Q, R, I, s, L, ET, replace_discharge_by_precipitation=False, linewidth=1.5):
"""
plots the outputs of the hydrological model using the same parameters.
Inputs :
- Q [m3/s] the total discharge (or the precipitation [mm/h])
- R [mm/h] the runoff -> possible to change unit if not convenient
- I [mm/h] the infiltration -> possible to change unit if not convenient
- s [-] the soil saturation
- L [mm/h] the leaching -> possible to change unit if not convenient
- ET [mm/h] the actual evapotranspiration
Output (plots) :
- Q [m3/s] the total discharge (or the precipitation [mm/h])
- R [mm/h] the runoff -> possible to change unit if not convenient
- I [mm/h] the infiltration -> possible to change unit if not convenient
- s [-] the soil saturation
- L [mm/h] the leaching -> possible to change unit if not convenient
- ET [mm/h] the actual evapotranspiration
"""
n_years=int(len(Q)/(365*24))
out = [Q, R, I, s, L, ET]
titres = ["Discharge [m3/s]", "Runoff [mm/h]", "Infiltration [mm/h]", "soil moisture [-]",\
"Leaching [mm/h]", "Evapotranspiration [mm/h]"]
units=["[m3/s]","[mm/h]","[mm/h]","[-]","[mm/h]","[mm/h]"]
if replace_discharge_by_precipitation:
titres[0] = "Precipitation"
units[0] = "[mm/h]"
lines = 2
col = 3
t = [2000 + i/365/24 for i in range(n_years*24*365)]
fig, axs = plt.subplots(lines, col,figsize=(18,10))
for i in range(lines):
for j in range(col):
plt.subplots_adjust(hspace =0.3,wspace=0.2)
axs[i, j].plot(t, out[j+3*i], linewidth = linewidth)
axs[i, j].set_title(titres[j+3*i],fontsize=20)
axs[i, j].set_xlabel("Time [years]")
axs[i, j].set_ylabel(units[j+3*i],fontsize=10)
title=" Time series - "+str(n_years) + " years"
plt.suptitle(title,fontsize=25)
plt.show()
return None
##############################################♀
def check_model(K_sat, c, t_sub, z, P, K_c, n_years):
out = hydr_model(K_sat, c, t_sub, z, P, K_c, n_years)
s = out[3]
P_tot = np.sum(P) # mm/h
R_tot = np.sum(out[1])
L_tot = np.sum(out[4])
ET_tot = np.sum(out[5])
q_sup_tot = np.sum(q_sup)
q_sub_tot = np.sum(q_sub)
testS = P_tot / (ET_tot + R_tot + L_tot + n*z*(s[-1]-s[0]))
testQ = (P_tot - ET_tot) / (q_sub_tot + q_sup_tot + n*z*(s[-1]-s[0]) + q_sup[-1]*t_sup + q_sub[-1]*t_sub)
return testS, testQ
#%% Finding the best parameters
# Define new parameters for the parameter optimization
theta_absolute_max = [5e-6, 10, 200, 1000]
ns_absolute_max = float('-inf')
def T_SA(i):
"""
fonction qui calcule la 'temperature liee a l'algorithme pour savoir si on
va voir ailleurs
"""
c_r = 1/1200 # cooling rate
return np.exp(-c_r*i)
def NS(Q, Q_observed, Q_averaged):
"""
indicateur de proximité du Q en entree avec le Q observe (en donnee de l'exo)
"""
# ne semble pas avoir de pb
a = np.sum( np.power( np.subtract(Q, Q_observed) , 2) )
b = np.sum( np.power( np.subtract(Q, Q_averaged) , 2) )
return 1 - a/b
iteration_max = 20e3
NS_list = np.zeros(int(iteration_max)+1)
NS_out = []
def opt_param(theta_start = [5e-6, 10, 200, 1000]):
global Q_obs
global theta_absolute_max
global ns_absolute_max
global NS_out
global NS_list
Q_avg = [np.mean(Q_obs) for i in Q_obs]
theta_old = theta_start.copy() # initial values of the parameters
theta_new = theta_old.copy()
theta_minmax = [[1e-7, 1e-5],
[1, 20],
[1, 400],
[1, 2000]] # min/max values of the parameters
theta_var = [np.diff(i)[0]/20 for i in theta_minmax] # variance of the parameter, equal to 5% of the range
# prepare the plot of the evolution of parameters
theta_list = np.zeros((4, iteration_max))
# parameters
ns_old = float("-inf") # value of the NS coefficient
n_sim = 0 # nb of simulations yet
n_sim_valid = 0 # nb of parameters accepted
seuil = 0.87 # seuil pour le NS coeff
print("Seuil choisi de : ", seuil)
print("Starting parameters : ", theta_old)
print("\n")
while ns_old < seuil:
if n_sim == iteration_max:
print("Iterations maximales dépassées pour la boucle principale")
break
# print(n_sim)
# generate new parameters
for i in range(4):
theta_new[i] = scipy.stats.truncnorm.rvs( \
(theta_minmax[i][0]-theta_old[i])/theta_var[i], \
(theta_minmax[i][1]-theta_old[i])/theta_var[i], \
loc = theta_old[i], scale = theta_var[i])
Q_mod = hydr_model(theta_new[0], theta_new[1], theta_new[2], theta_new[3], precipitation, K_c, 6)[0]
ns_new = NS(Q_mod, Q_obs, Q_avg)
if ns_new > ns_old:
if ns_new > ns_absolute_max:
theta_absolute_max = theta_new.copy()
ns_absolute_max = ns_new
theta_old = theta_new.copy()
ns_old = ns_new
NS_list[n_sim_valid] = ns_new
print(theta_new)
for i in range(4):
theta_list[i][n_sim_valid] = theta_new[i]
n_sim_valid += 1
elif np.random.uniform() < np.exp(-abs(ns_new-ns_old)/T_SA(n_sim)):
theta_old = theta_new.copy()
ns_old = ns_new
NS_list[n_sim_valid] = ns_new
n_sim_valid += 1
print("Iteration "+str(n_sim)+" / Best NS = "+str(ns_absolute_max)+" / "+str(theta_absolute_max), end="\r")
n_sim += 1
NS_list[n_sim_valid:]
plt.figure()
plt.grid(True)
ax = plt.gca()
ax.set_title("Convergence of the NS indicator when determining optimal parameters",fontsize=20)
ax.set_ylabel("NS indicator")
ax.set_xlabel("Number of accepted iteration")
plt.plot(NS_list[:n_sim_valid], label='NS indicator')
plt.show()
plt.figure(figsize=(30,20))
plt.grid(True)
# K_sat
plt.subplot(2,2,1)
plt.subplots_adjust(hspace =0.4,wspace=0.1)
ax=plt.gca()
plt.plot(theta_list[0][:n_sim_valid])
ax.set_title("K_sat convergence",fontsize=20)
ax.set_xlabel("Number of accepted iteration", fontsize=20)
ax.set_ylabel("K_sat [m/s]", fontsize=15)
# K_sat
plt.subplot(2,2,2)
plt.subplots_adjust(hspace =0.4,wspace=0.1)
ax=plt.gca()
plt.plot(theta_list[1][:n_sim_valid])
ax.set_title("c convergence",fontsize=20)
ax.set_xlabel("Number of accepted iteration", fontsize=20)
ax.set_ylabel("c [-]", fontsize=15)
# K_sat
plt.subplot(2,2,3)
plt.subplots_adjust(hspace =0.4,wspace=0.1)
ax=plt.gca()
plt.plot(theta_list[2][:n_sim_valid])
ax.set_title("t_sub convergence",fontsize=20)
ax.set_xlabel("Number of accepted iteration", fontsize=20)
ax.set_ylabel("t_sub [h]", fontsize=15)
# K_sat
plt.subplot(2,2,4)
plt.subplots_adjust(hspace =0.4,wspace=0.1)
ax=plt.gca()
plt.plot(theta_list[3][:n_sim_valid])
ax.set_title("z convergence",fontsize=20)
ax.set_xlabel("Number of accepted iteration", fontsize=20)
ax.set_ylabel("z [mm]", fontsize=15)
plt.suptitle("Markov chains of the parameters",fontsize=30)
return ns_absolute_max, theta_absolute_max, theta_list
# Valeur empirique trouvée par itération de l'algo
# [8.70000000e-07, 7.93257754e+00, 9.86297945e+01, 3.79904507e+02], NS = 0.864
#%% Precipitation modelling
def parametres(P):
"""
INPUT:
- Precipitation [mm/h]
OUTPUT: parameters that describe the rain properties
- lambda [-] frequency of rainfall events
- alpha [mm] average precipitation per rainy day
- monthly averaged mean precipitation [mm/day]
- monthly averaged precipitation standard deviation [mm/day]
"""
years = int(len(P)/(365*24))
P_jour = [np.sum(P[24*k:24*(k+1)]) for k in range(years*365) ] # [mm/day] for each day
n_rainy_day=[0]*12
I_rain=[0]*12 # [mm/h]
month_P=[[]]*12
#I_rain and month_P are the same ??
for year in range(years):
for month in range(12):
for k in range(month_start[month],month_end[month]+1):
x = P_jour[365*year+k]
month_P[month] = month_P[month]+[x]
if x != 0:
n_rainy_day[month] += 1
I_rain[month] += P_jour[365*year+k]
lambda_p = [n_rainy_day[k]/(day_month[k]*years) for k in range(12)]
alpha = [I_rain[k]/n_rainy_day[k] for k in range(12)]
mean_P = [np.mean(month_P[k]) for k in range(12)]
std_P = [np.std(month_P[k]) for k in range(12)]
return(lambda_p,alpha,mean_P,std_P)
############################################
def rain_gen(years=100, plot=True, climate_change=False, alpha_c=alpha_c):
"""
INPUT:
- years: number of year we want to simulate
- plot: do we want to plot the statistics od the simulation ?
If yes: plot of lambda, alpha, mean precipitation and mean deviation observed vs generated
- climate_change : added to compute in a climate change scenario
"""
#alpha lambda
#precipitationj=[sum(precipitation[24*k:24*k+24]) for k in range(0,6*365) ]
lambda_,alpha,mean_P,std_P=parametres(precipitation)
title="Statistics of the generated precipitation"
obs="Observed"
gen="Generated"
if climate_change:
# We are in climate change scenarios,
#alpha is modified by the percent of changes in monthly mean rainfall intensity
alpha_past=alpha.copy()
lambda_past=lambda_.copy()
for i in range(12):
alpha[i]=(1+alpha_c[i]/(100))*alpha[i]
lambda_[i]=(1+lambda_c[i]/100)*lambda_[i]
title=title+" - climate change scenario"
obs="Current observation"
gen="Future simulation"
output = [0 for i in range(365*years)]
total_day = 0
for y in range(years):
for m in range(12):
for d in range(day_month[m]):
# Does it rain ?
if rd.random() < lambda_[m]:
output[total_day] = rd.expovariate(1/alpha[m])
total_day += 1
P_gen=downscaling(output)
#statistic
if plot:
#lambda_gen,alpha_gen,mean_P_gen,std_P_gen=parametres([sum(P_gen[24*k:24*k+24]) for k in range(0,years*365) ])
lambda_gen,alpha_gen,mean_P_gen,std_P_gen=parametres(P_gen)
figure=plt.figure(figsize=(30,12))
plt.grid(True)
# lambda
plt.subplot(2,2,1)
plt.subplots_adjust(hspace =0.4,wspace=0.1)
ax=plt.gca()
if climate_change:
plt.plot(month_name,lambda_past,marker='o',label=obs)
else:
plt.plot(month_name,lambda_,marker='o',label=obs)
plt.plot(lambda_gen,marker='o',label=gen)
plt.xticks(rotation=50,fontsize=15)
ax.set_title("Lambda",fontsize=20)
ax.set_ylabel("[-]", fontsize=15)
ax.legend()
# alpha
plt.subplot(2,2,2)
ax=plt.gca()
plt.subplots_adjust(hspace =0.4,wspace=0.1)
if climate_change:
plt.plot(month_name,alpha_past,marker='o',label=obs)
else:
plt.plot(month_name,alpha,marker='o',label=obs)
plt.plot(month_name,alpha_gen,marker='o',label=gen)
ax.set_title("Alpha",fontsize=20)
ax.set_ylabel("[mm]", fontsize=15)
plt.xticks(rotation=50,fontsize=15)
ax.legend()
# mean
plt.subplot(2,2,3)
ax=plt.gca()
plt.subplots_adjust(hspace =0.4,wspace=0.1)
plt.plot(month_name,mean_P,marker='o',label=obs)
plt.plot(month_name,mean_P_gen,marker='o',label=gen)
ax.set_title("Average daily precipitation",fontsize=20)
ax.set_ylabel("[mm / day]", fontsize=15)
plt.xticks(rotation=50,fontsize=15)
ax.legend()
# std deviation
plt.subplot(2,2,4)
ax=plt.gca()
plt.subplots_adjust(hspace =0.4,wspace=0.1)
plt.plot(month_name,std_P,marker='o',label=obs)
plt.plot(month_name,std_P_gen,marker='o',label=gen)
ax.set_title("Standard deviation",fontsize=20)
ax.set_ylabel("[mm / day]", fontsize=15)
plt.xticks(rotation=50,fontsize=15)
ax.legend()
plt.suptitle(title,fontsize=30)
return (P_gen)
#%% Dam modelling
def vol_rat_curve(area_rat_curve):
"""
input :
- a list of the area [m2] of the lake for each level [m] of the lake
area_rat_curve[i] should be equal to the area of the lake at height i meters
Output :
- a list of the same size of the input describing the volume [m3] for each
level.
Out[i] is the volume [m3] if the lake is at height i [m]
"""
n = len(area_rat_curve)
ans = [0 for i in range(n)]
for i in range(1,n):
ans[i] = (area_rat_curve[i-1] + area_rat_curve[i])/2 + ans[i-1]
return ans
#################################
def lvl_to_vol(level, volume_rating_curve):
"""
input :
- a level [m] at which we want to compute the volume. Can be a float.
- volume_rating_curve a list describing the volume [m3] for each level
volume_rating_curve[i] should be the volume at lake height i [m]
Output :
- the volume [m3] at the desired lake height
"""
if level > len(volume_rating_curve):
raise ValueError("The level is too high ! (" + str(level) + \
"m for a maximum level of " + str(len(volume_rating_curve)) + \
")")
# partie entière
i = int(np.floor(level))
# partie décimale
dec = level - i
# bornes de l'interpolation
a = volume_rating_curve[i]
b = volume_rating_curve[i+1]
return a + (b-a)*dec
###########################################
def vol_to_lvl(volume, volume_rating_curve):
"""
Input :
- volume [m3] the volume of the reservoir we want to calculate the level
- volume_rating_curve a list describing the volume [m3] for each level
volume_rating_curve[i] should be the volume at lake height i [m]
Output :
- the level [m] corresponding to the given volume and VRC
"""
vrc = volume_rating_curve
if volume > vrc[-1]:
raise ValueError("The given volume of the reservoir is bigger than \
the actual total capacity of the reservoir !" + \
str(volume) + " given for a maximum of " + \
str(vrc[-1]))
for i in range(len(vrc)-1):
if volume >= vrc[i] and volume <= vrc[i+1]:
dec = (volume - vrc[i]) / (vrc[i+1] - vrc[i])
return i+dec
################################
def Q_S(P,ET):
"""
Input :
- P [mm/h] precipitation as a list of length n
- ET [mm/h] evapotranspiration as a list of length n (same length required !)
Output :
- the Q_sup [m3/s] as a list of length n required to satisfy the crop
and city needs (local parameters are given inside the function code)
"""
## Returns the discharge that need to supply the city and the crops in m3/h
# Parameters
A_crop = 5 #[km^2]
etha_crop=0.8 # [-]
etha_p = 0.4 # [-]
# variable initialization
n=len(P)
Q_I=[0]*n # m3/s the needs of the crops
if n != len(ET):
raise IndexError("Both parameters are not the same length ! (" + \
str(n)+" for precipitation vs "+str(len(ET))+ \
" for evapotranspiration)")
for i in range(n):
Q_I[i] = max((( ET[i] - etha_p*P[i])*1e-3/3600*A_crop*(1e6))/etha_crop,0)
Q_city=[Qcity]*n #[m3/s]
return np.add(Q_I, Q_city)
############################# Reservoir routing
def Q_347(Q, plot=False):
"""
Input :
- Q [m3/s] (or another unit) the input discharge
- plot (default = False) plots the discharge curve and the output Q_347
/!\ The units displayed on the graph are set to m3/s /!\
Output :
- Q_347 [m3/s] (or the other unit) the discharge that is exceeded 95%
of the time
"""
n=len(Q)
sort_Q=sorted(Q,reverse=True)
rank = int(n*95/100)-1
p_exceedance=[k/n for k in range (1,n+1)]
Q347=sort_Q[rank]
if plot:
figure=plt.figure(figsize=(10,5))
plt.semilogy(p_exceedance,sort_Q, label="Discharge duration curve")
plt.semilogy(p_exceedance,[Q347]*n,color="red",linestyle='-.',label="Minimum Flow")
plt.title("Discharge Duration Curve - Minimum Flow = "+str(round(Q347,2)) + " m3/s", fontsize=15)
#plt.plot(p_exceedance,[sort_Q[rank]]*(n),color="red")
plt.xlabel("probability of exceedance [-]")
plt.ylabel("Discharge [m3/s]")
plt.legend()
plt.show()
return Q347
#%% reservoir routing
############## MAIN
#parameters of the reservoir
Cqg = 0.6 # [-] sluice gate discharge coefficient
Cqs = 0.7 # [-] spillway discharge coefficient
Lspill = 140 # [m] spillway effective length
p = 19 # [m] difference between spillway level and minimum level
#parameters of power plant
QT = 30 # [m/s] design discharge of the hydro PP
D = 3.6 # [m]
Lp = 1200 # [m]
ks = 0.5 # [mm]
eta = 0.75 # [-] Careful, more than one eta
Deltaz = 75 # [m] difference in height between the elevation of the empty lake
# (headwater) and the tailwater
lmin_HU = 9 # [m] min height for electricity generation
Qlim = 100 #[m3/s]
g = 9.806 # [m/s2] gravity
f = (1/(-2*np.log(ks/(1000*D*3.7))))**2 #Colebrook equation
A_pipe=np.pi*(D/2)**2
kL = f*Lp/(2*g*D) * 1.5 / A_pipe**2 # [m / (m3/s)^2] Loss coefficient
#Power=9806*net_head*Q*eta/1000000 %[MW]
gamma=g*1000
Energy_price=75
# Reservoir routing
def reservoir_routine(Q,P,ET,volume_rating_curve,lmax_HU=15):
"""
Inputs :
- Q [m3/s] the flow entering the dam
- P [mm/h] the precipitation over the whole basin
- ET [mm/h] the evapotranspiration
- volume_rating_curve [m] - [m3] the discrete function between the level
of the lake and its volume
- lmax_HU [m] maximum level for hydropower production
Output :
V,l,A_sluice,Q_out,Q_HU,Q_g)
- V [m3] a list of length n describing the total volume in the dam
- l [m] a list of length n describing the level in the dam
- A_sluice [m2] a list of length n describing the open area of the sluice
to let the ater out in the river
- Q_out [m3/s] a list of length n describing the flow that exits the
dam to the river (NOT power generation !)
- Q_HU [m3/s] a list of length n describing the flow used for power
generation (does NOT to river)
- Q_g [m3/s] a list of length n describing the flow that goes through
the sluice gate only (NOT the spillway)
- Pow [Watt] turbine power generation
- profit [CHF]
- p_flood
- E_annual [GWh]
TO-DO :
- integrate the power generation calculation ? (not sure)
"""
# Variable to calculate
dt = 3600 # [s] time step integration
Q347 = Q_347(Q,plot=False) # [m3/s]
n = len(Q)
Q_ind = Q_S(P,ET) # [m3/s]
# variable initialization
V = [0]*n # [m3]
l = [0]*n # [m] level of the reservoir depending on time